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Taking the 1st Implicit Derivative

3

Taking derivatives implicitly is a process saved for instances in which the function in question is not set out or able to be changed into a y = x format.

Take, for example, a function like this:

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No matter what is done to this function, x and y cannot be completely separated onto their own sides into a y = x format. Therefore, the only way to take the derivative of this function is to take the derivative implicitly.

Taking an implicit derivative is nearly identical to that of taking a derivative normally, except you must multiply all derivatives of y by dy/dx.

Here is how you take the derivative of the above function:

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=

2

4y (dy/dx) + (x (dy/dx) + 2xy) - 1 = 0 --> 4y (dy/dx) + x (dy/dx) +2xy - 1 = 0

4y (dy/dx) + x (dy/dx) = 1 - 2xy --> (dy/dx)(4y  + x  ) = 1 - 2xy

3

3

2

3

2

2

2

4

y  + x y - x = 31

(dy/dx)

1 - 2xy 

4y +x 

3

2

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